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Showing posts with label Graphics. Show all posts
Showing posts with label Graphics. Show all posts

Getting Properties of an image[VC++.NET]

Getting Properties of an Image

Language: VC++.NET

Author: Aamir Mustafa

Introduction:

This simple article will show how to get image properties. In this article I will load a photo and then its property will be shown. it will display all the properties of an image like name, image type, image size, its resolution.

How to show property:

Create an empty project and add following controls on the form.

Control

Properties

Form

Name=Form1

Text= Properties

Width=554

Height=224

Button

Name= btnLoad

Text= Load Photo

ListView

Name= lstProperties

Width=329

Height=149

Scrollable=False

Font Style=Bold

Font Size=8

ForeColor=Coral

PictureBox

Name= pic

Width=117

Height=149

BorderStyle=FixedSingle

SizeMode=StretchImage

After doing that go to view code and add following code below in public area of class Form1.

public:

Bitmap ^bitmapImage;

String ^imageFile;

After that add following just below the above code

Here we are initializing the List View so when first our program runs so we can see two columns, one for Property and second for Property value. Both columns will be added when we first launch our program. Both columns have equal width. Type of View will be detail so we can show properties in detail like a table and we will set Grid Lines to true so that we can show grid lines. We will write following code in Form1 constructor.

Form1(void)

{

InitializeComponent();

lstProperties->View=View::Details;

lstProperties->Columns->Add("Property",Convert::ToInt32(lstProperties->Width*50/100));

lstProperties->Columns->Add("Value",Convert::ToInt32(lstProperties->Width*50/100));

lstProperties->GridLines=true;

}

Now write a function called GetProperties which gets the properties of an image and shows them in list view.

private:

void GetProperties()

{

lstProperties->Items->Clear();

lstProperties->Items->Add(gcnew ListViewItem(gcnew array { "Name", System::IO::Path::GetFileNameWithoutExtension(imageFile) }));

lstProperties->Items->Add(gcnew ListViewItem(gcnew array {"Width",bitmapImage->Width.ToString()+" Pixels"}));

lstProperties->Items->Add(gcnew ListViewItem(gcnew array {"Height",bitmapImage->Height.ToString()+" Pixels"}));

lstProperties->Items->Add(gcnew ListViewItem(gcnew array {"Vertical Resolution",bitmapImage->VerticalResolution.ToString()+" Pixels/Inch"}));

lstProperties->Items->Add(gcnew ListViewItem(gcnew array {"Horizontal Resolution",bitmapImage->HorizontalResolution.ToString()+" Pixels/Inch"}));

lstProperties->Items->Add(gcnew ListViewItem(gcnew array {"Pixel Format",bitmapImage->PixelFormat.ToString()}));

lstProperties->Items->Add(gcnew ListViewItem(gcnew array {"Pallete Flags",bitmapImage->Palette->Flags.ToString()}));

}

After that add following code to the load button’s click event. This opens a dialog to load picture from the local disk.

private: System::Void btnLoad_Click(System::Object^ sender, System::EventArgs^ e)

{

FileDialog ^fileDialog = gcnew OpenFileDialog();

fileDialog->Filter = "JPG (*.jpg)|*.jpg| Bitmap (*.bmp)|*.bmp|GIF (*.gif)|*.gif|JPEG (*.jpeg)|*.jpeg|PNG (*.png)|*.png|TIFF (*.tif)|*.tif|All Files (*.*)|*.*";

fileDialog->ShowDialog(this);

pic->SizeMode = PictureBoxSizeMode::StretchImage;

imageFile = fileDialog->FileName;

if (imageFile == System::String::Empty)

return;

pic->Image = Image::FromFile(imageFile);

bitmapImage = gcnew Bitmap(imageFile);

GetProperties();

}

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Getting Properties of an image[VB.NET]

Getting Properties of an Image

Language: VB.NET

Author: Aamir Mustafa

Introduction:

This simple article will show how to get image properties. In this article I will load a photo and then its property will be shown. it will display all the properties of an image like name, image type, image size, its resolution.


How to show property:

Create an empty project and add following controls on the form.

Control

Properties

Form

Name=Form1

Text= Properties

Width=554

Height=224

Button

Name= btnLoad

Text= Load Photo

ListView

Name= lstProperties

Width=329

Height=149

Scrollable=False

Font Style=Bold

Font Size=8

ForeColor=Coral

PictureBox

Name= pic

Width=117

Height=149

BorderStyle=FixedSingle

SizeMode=StretchImage



After doing that go to view code and add following code below Public Class Form1

Dim bitmapImage As Bitmap

Dim imageFile As String

After that add following just below the above code

Here we are initializing the List View so when first our program runs so we can see two columns, one for Property and second for Property value.

Public Sub New()

InitializeComponent()

lstProperties.View = View.Details

lstProperties.View = View.Details

lstProperties.Columns.Add("Property", Convert.ToInt32(lstProperties.Width * 50 \ 100))

lstProperties.Columns.Add("Value", Convert.ToInt32(lstProperties.Width * 45 \ 100))

lstProperties.GridLines = True

End Sub

Now write a function called GetProperties which gets the properties of an image and shows them in list view.

Private Sub GetProperties()

lstProperties.Items.Clear() ' clear the list view

lstProperties.Items.Add(New ListViewItem(New String() {"Name", System.IO.Path.GetFileNameWithoutExtension(imageFile)})) 'this will show name of image but not with extension

lstProperties.Items.Add(New ListViewItem(New String() {"Type", System.IO.Path.GetExtension(imageFile)})) 'this will show image type like JPEG

lstProperties.Items.Add(New ListViewItem(New String() {"Size", New System.IO.FileInfo(imageFile).Length.ToString() & " Bytes"})) 'this will show image size in bytes

lstProperties.Items.Add(New ListViewItem(New String() {"Width", pic.Width.ToString() & " Pixels"})) 'this will show image width

lstProperties.Items.Add(New ListViewItem(New String() {"Height", pic.Height.ToString() & " Pixels"})) 'this will show image height

lstProperties.Items.Add(New ListViewItem(New String() {"Vertical Resolution", bitmapImage.VerticalResolution.ToString() & " Pixels/Inch"})) 'this will show Vertical Resolution

lstProperties.Items.Add(New ListViewItem(New String() {"Horizontal Resolution", bitmapImage.HorizontalResolution.ToString() & " Pixels/Inch"})) 'this will show Horizontal Resolution

lstProperties.Items.Add(New ListViewItem(New String() {"Pixel Format", bitmapImage.PixelFormat.ToString()})) 'this will show pixel format.

lstProperties.Items.Add(New ListViewItem(New String() {"Palette Flags", bitmapImage.Palette.Flags.ToString()})) 'this will show pallete flags

End Sub

After that add following code to the load button’s click event. This opens a dialog to load picture from the local disk.

Private Sub btnLoad_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btnLoad.Click

Dim fileDialog As FileDialog = New OpenFileDialog()

fileDialog.Filter = "JPG (*.jpg)|*.jpg| Bitmap (*.bmp)|*.bmp|GIF (*.gif)|*.gif|JPEG (*.jpeg)|*.jpeg|PNG (*.png)|*.png|TIFF (*.tif)|*.tif|All Files (*.*)|*.*"

fileDialog.ShowDialog(Me)

pic.SizeMode = PictureBoxSizeMode.StretchImage

imageFile = fileDialog.FileName

If imageFile = String.Empty Then

Return

End If

pic.Image = Image.FromFile(imageFile)

bitmapImage = New Bitmap(imageFile)

GetProperties() ‘call GetProperties method

End Sub

Note:

If you want to get size of the image in Kilo Bytes then you can do it as follow

System.IO.FileInfo(imageFile).Length.ToString()\1024 & lstProperties.Items.Add(New ListViewItem(New String() {"Size", New" KB"})) 'this will show image size in kilo bytes


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Draw a background with a rotating color gradient in Visual Basic .NET

TitleDraw a background with a rotating color gradient in Visual Basic .NET
DescriptionThis example shows how to draw a background with a rotating color gradient in Visual Basic .NET.
Keywordscolor gradient, moving gradient, rotating gradient, animation, VB.NET



When the form's Timer fires, the event handler invalidates the drawing area PictureBox.

The PictureBox's Paint event handler makes a LinearGradientBrush. The rectangle the gradient covers is slightly larger than the PictureBox's client rectangle. The brush uses the angle m_Theta to determine the gradient's angle.

The program fills the PictureBox with the brush. It then updates m_Theta so the gradient rotates next time.

Finally the program draws some text over the colored background.


Private m_Theta As Single = 0
Private m_Delta As Single = 10

Private Sub tmrRotate_Tick(ByVal sender As System.Object, _
ByVal e As System.EventArgs) Handles tmrRotate.Tick
picCanvas.Invalidate()
End Sub

Private Sub picCanvas_Paint(ByVal sender As Object, ByVal e _
As System.Windows.Forms.PaintEventArgs) Handles _
picCanvas.Paint
Dim rect As New Rectangle(-3, -3, _
picCanvas.ClientSize.Width + 6, _
picCanvas.ClientSize.Height + 6)
Dim br As New LinearGradientBrush(rect, Color.Red, _
Color.Blue, m_Theta)
e.Graphics.Clear(picCanvas.BackColor)
e.Graphics.FillRectangle(br, Me.ClientRectangle)
br.Dispose()
m_Theta += m_Delta

Dim string_format As New StringFormat
string_format.Alignment = StringAlignment.Center
string_format.LineAlignment = StringAlignment.Center
e.Graphics.DrawString("Some Text", Me.Font, _
Brushes.Black, _
picCanvas.ClientSize.Width \ 2, _
picCanvas.ClientSize.Height \ 2, _
string_format)
End Sub
Download Source Code here

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